PUZZLE-MIND WORKOUT 2
PUZZLE-MIND WORKOUT 2
HAI GUYS,
In this Sunday, I am gonna ask two puzzles to you
guys it's very simple only. The same condition, don't google it kick your mind
solve a puzzle and to find a solution.
OK!
today puzzle???
1. THE WHEEL
PUZZLE:
Locate the numbers 1 to 19 in
the 19 circles, so that wherever there are three in a straight line they shall
add up to 30. It is, of course, very easy.
2.WATER MEASUREMENT:
A maid was sent to the brook
with two vessels that exactly measured 7 liters and 11 liters respectively.
She
had to bring back exactly 2 liters of water. What is the smallest possible
number of transactions necessary? A "transaction" is filling a
vessel, or emptying it, or pouring from one vessel to another.
😀😀😀COMMENT THE ANSWER BELOW 😀😀😀
"I will give you the
solutions for these two questions you may expect at next Sunday"
OK!!!! Last Sunday I asked
one puzzle I don't know how members are solved but, I hope you may try to solve
the puzzle.
Solution:
I will give you the eg: We
take the 50th door which was closed initially, On walk 1 the person progresses
to open it, on walk 2 the person progresses to close it, on walk 5 he opens it
again, on walk 10 he again closes it, on walk 25 he opens it, on walk 50 he
toggles the door as close.
So what we observed here is
the door which has even no. of factors, the final state of the door will be
closed, there is an even number so the final state of the door will be closed
and at the same time, if the door which has odd no. of factors, the final state
of the door will be opened.
"Our question is all
such doors which will remain open at the end of the 100th walk"
There are two methods to
solve one is manual and another one is a smart approach
In the manual approach, hard
to find but it can.
In a smart approach, lets we
consider the previous eg: 50th door.
The factors are
1,2,5,10,25,50 I put the line in center (EVEN NO. OF FACTORS)
you will understand after
seeing the image;
We multiply left side number
1 with right side number 50 so we get an answer=50, (2*25, 5*10) vice versa.
Imagine the door number
having odd no. of factors for eg: A dual number 'X' which is having 5 factors
F1, F2, F3, F4, F5.
We multiply left side number
F1with right side number F5 so we get an answer=X, (F2*F4) then F3 is alone now
which is at the middle.
We know that this middle number (F3) also a factor of
'X' so it should be multiplied by the many other factors from these numbers to
get the value 'X' since all other factors have already made a pair so for this
middle number factor the only way to multiply with that same factor (F3*F3)
which is equal to dual number 'X' so what you get multiply a number with
itself, we get a perfect square.
This is a matter which we have considered the
numbers what all are the perfect squares, those are odd no. of factors.
EXAMPLE:
16 is the perfect square which has 5 factors, so this is odd no. of factors. |
"SO, THAT IS THE FINAL
ANSWER WILL BE THE
I know its a complicated
question I hope this explanation will be enough to understand for you guys.😃😃😃😃
😃😃😃IN THE BELOW LINK CONTAINS NEXT PUZZLES😃😃😃
https://in-no-way-tive.blogspot.com/2019/06/puzzle-mind-workout-3-hai-guys-todays.html
CLICK
THIS LINK FOR PREVIOUS QUESTION:
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